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Section 6.2 Angle Position and Arc Length (TR2)

Subsection 6.2.1 Activities

Definition 6.2.2.

Two angles are called coterminal angles if they have the same terminal side when drawn in standard position.

Activity 6.2.3.

Consider the angle given below:
(a)
Find two angles larger than \(60^\circ\) that are coterminal to \(60^\circ\text{.}\)
Answer.
\(420^\circ\text{,}\) \(780^\circ\text{,}\) among others.
(b)
Find two angles smaller than \(60^\circ\) that are coterminal to \(60^\circ\text{.}\)
Answer.
\(-300^\circ\text{,}\) \(-660^\circ\text{,}\) among others.

Observation 6.2.4.

For any angle \(\theta\text{,}\) the angle \(\theta + k\cdot 360^\circ\) is coterminal to \(\theta\) for any integer \(k\text{.}\)

Remark 6.2.5.

Since there are many coterminal angles for any given angle, it is convenient to systematically choose one for every angle. For a given angle, we typically choose the smallest positive coterminal angle to work with instead.

Definition 6.2.6.

If \(\theta\) is an angle, there is a unique angle \(\alpha\) with \(0 \leq \alpha \lt 360^\circ\) (or \(0\leq \alpha \lt 2\pi\)) such that \(\alpha\) and \(\theta\) are coterminal. This angle \(\alpha\) is called the principal angle of \(\theta\text{.}\)

Remark 6.2.8.

Recall that the circumference of a circle of radius \(r\) is \(2 \pi r\text{.}\) We will use this to determine the lengths of arcs on a circle.

Activity 6.2.9.

Consider the portion of a circle of radius \(1\) graphed below.

Activity 6.2.10.

Consider the portion of a circle of radius \(3\) graphed below.

Observation 6.2.11.

For a sector of angle \(\theta\) and radius \(r\text{,}\) we can use proportions to find the length of the arc, \(s\text{.}\) If \(\theta\) is measured in degrees, we have \(s=\frac{\theta}{360^\circ}\left(2\pi r\right)\text{,}\) which simplifies to
\begin{equation*} s=\frac{\theta}{180^\circ}\pi r\text{.} \end{equation*}
In radians, the formula is even nicer: \(s=\frac{\theta}{2\pi}\left(2 \pi r\right)\text{,}\) which simplifies to
\begin{equation*} s=\theta r\text{.} \end{equation*}

Activity 6.2.12.

Find the lengths of the arcs described below.
(c)
The length of the arc of a sector of measure \(\dfrac{5\pi}{6}\) of a circle of radius \(3\text{.}\)
Answer.
\(\frac{5\pi}{2}\)
(d)
The length of the arc of a sector of measure \(\dfrac{11\pi}{12}\) of a circle of radius \(6\text{.}\)
Answer.
\(\frac{11\pi}{2}\)

Remark 6.2.13.

Recalling that the area of a circle of radius \(r\) is \(\pi r^2\text{,}\) we can use this same idea of proportions to find the area of a sector of a circle.

Activity 6.2.14.

Consider the portion of a circle of radius \(1\) graphed below.

Activity 6.2.15.

Consider the portion of a circle of radius \(3\) graphed below.

Observation 6.2.16.

For a sector of angle \(\theta\) and radius \(r\text{,}\) we can use proportions to find the area of the arc. If \(\theta\) is measured in degrees, we have \(A=\frac{\theta}{360^\circ}\left(\pi r^2\right)\text{.}\) In radians, the formula is even nicer: \(A=\frac{\theta}{2\pi}\left(\pi r^2\right)\text{,}\) which simplifies to
\begin{equation*} A=\frac{1}{2}\theta r^2\text{.} \end{equation*}

Activity 6.2.17.

Find the areas of each sector described below.

Subsection 6.2.2 Exercises