If a particle has position function \(s = f(t)\text{,}\) where \(t\) is measured in seconds and \(s\) is measured in meters, then the derivative of the position function tells us how the position is changing over time, so \(f'(t)\) gives us the (instantaneous) velocity in meters per second. Also, the derivative of the velocity gives us the change in velocity over time, so so \(f''(t)\) gives us the (instantaneous) acceleration in meters per second squared. Summarizing,
\(v(t) = f'(t)\) is the velocity of the particle in \(m/s\text{.}\)
Find the total distance that the particle travels in the time interval \(0 \leq t \leq 5\text{.}\) Careful: the total distance is not the same as the displacement (the change in position)! Compute how much the particle moves up and add it to how much the particle moves down.
In some cases, we want to also consider the speed of a particle, which is the absolute value of the velocity. In symbols \(|v(t)|= |f'(t)|\) is the speed of the particle. A particle is speeding up when the speed is increasing.
If \(C (x)\) is the cost of producing \(x\) items and \(R(x)\) is the revenue from selling \(x\) items, then \(P(x)= R(x) - C(x)\) is the profit. We can study their derivatives, the marginals
\(C'(x)\) is the marginal cost, the rate of change of the cost per unit change in production;
\(P'(x)= R'(x) - C'(x)\) is the marginal profit, the rate of change of the profit per unit change in sales (assuming we are selling all the items produced).
The manager of a computer shop has to decide how many computers to store in the back of the shop. If she stores a large number, she has to pay extra in storage costs. If she stores only a small number, she will have to reorder more often, which will involve additional handling costs. She has found that if she stores \(x\) computers, the storage and handling costs will be \(C\) dollars, where
What is the fixed cost of the computer shop, the cost when no computers are in storage? In practical terms this may account for rent and utilities expenses.
Now suppose that \(x\) computers give revenue \(R(x) = 1000x\text{.}\) What is the marginal revenue? What is the real world interpretation of your finding?
Find a formula for the profit function \(P(x)\) and find the marginal profit using the marginal revenue and the marginal cost (assuming the number of items produced and sold is equal and given by \(x\)).
A gizmo is sold for \(\$63\) per item. Suppose that the number of items produced is equal to the number of items sold and that the cost (in dollars) of producing \(x\) gizmos is given by the following function:
Consider a cup of coffee initially at \(110^\circ\)F. The said cup of coffee was forgotten this morning in my living room where the thermostat is set at \(72^\circ\)F. I also observed that when I initially prepared the coffee, the temperature was decreasing at a rate of \(3.8\) degrees per minute.
In the long run, what temperature do you expect the coffee to tend to? Use this information in the model \(y=ae^{-kt}+c\) to determine the value of \(c\text{.}\)
The scenario also gives you information about the value of the rate of change at \(t=0\text{.}\) Use this additional information to determine the model \(y=ae^{-kt}+c\) completely.
You should find that the temperature model for this coffee cup is \(y= 72 + 38 e^{-0.1t}\text{.}\) Explain how the values of each parameter connects to the information given.