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Section 6.1 Average Value (AI1)
Learning Outcomes
Compute the average value of a function on an interval.
Subsection 6.1.1 Activities
Activity 6.1.1 .
Suppose a car drives due east at 70 miles per hour for 2 hours, and then slows down to 40 miles per hour for an additional hour.
(a)
How far did the car travel in these 3 hours?
\(110\) miles
\(150\) miles
\(180\) miles
\(220\) miles
(b)
What was its average velocity over these 3 hours?
\(55\) miles per hour
\(60\) miles per hour
\(70\) miles per hour
\(75\) miles per hour
Activity 6.1.2 .
Suppose instead the car starts with a velocity of
\(30\) miles per hour, and increases velocity linearly according to the function
\(v(t)=30+20t\) so its velocity after three hours is
\(90\) miles per hour.
(a)
How can we model the carβs distance traveled using calculus?
Integrate velocity, because position is the rate of change of velocity.
Integrate velocity, because velocity is the rate of change of position.
Differentiate velocity, because position is the rate of change of velocity.
Differentiate velocity, because velocity is the rate of change of position.
(b)
Then, which of these expressions is a mathematical model for the carβs distance traveled after 3 hours?
\(\displaystyle \int (30+20t)\,dt\)
\(\displaystyle \int (30t+10t^2)\,dt\)
\(\displaystyle \int_0^3 (30+20t)\,dt\)
\(\displaystyle \int_0^3 (30t+10t^2)\,dt\)
(c)
How far did the car travel in these 3 hours?
\(110\) miles
\(150\) miles
\(180\) miles
\(220\) miles
(d)
Thus, what was its average velocity over three hours?
\(55\) miles per hour
\(60\) miles per hour
\(70\) miles per hour
\(75\) miles per hour
Definition 6.1.4 .
Given a function \(f(x)\) defined on \([a,b]\text{,}\) itβs average value is defined to be
\begin{equation*}
\frac{1}{b-a}\int_a^b f(x) \,dx\text{.}
\end{equation*}
Activity 6.1.5 .
(a)
Which of the following expressions represent the average value of \(f(x)=-12 \, x^{2} + 8 \, x + 4\) over the interval \([-1, 2]\text{?}\)
\(\displaystyle \displaystyle \frac{1}{3}\int_{-1}^{2}\left(-12 \,x^{2} + 8 \, x + 4 \right) dx\)
\(\displaystyle \displaystyle \frac{-1}{1}\int_{1}^{2}\left(-12 \,x^{2} + 8 \, x + 4 \right) dx\)
\(\displaystyle \displaystyle \frac{1}{2}\int_{1}^{2}\left(-12 \,x^{2} + 8 \, x + 4 \right) dx\)
\(\displaystyle \displaystyle \frac{-1}{4}\int_{-1}^{2}\left(-12 \,x^{2} + 8 \, x + 4 \right) dx\)
(b)
Show that the average value of
\(f(x)=-12 \, x^{2} + 8 \, x + 4\) over the interval
\([-1, 2]\) is
\(-4\text{.}\)
Activity 6.1.6 .
(a)
(b)
Activity 6.1.7 .
Find the average value of
\(\displaystyle g(t)=\frac{t}{t^2+1}\) on the interval
\([0, 4]\text{.}\)
Activity 6.1.8 .
A shot of a drug is administered to a patient and the quantity of the drug in the bloodstream over time is
\(q(t)=3te^{-0.25t}\text{,}\) where
\(t\) is measured in hours and
\(q\) is measured in milligrams. What is the average quantity of this drug in the patientβs bloodstream over the first 6 hours after injection?
Activity 6.1.9 .
Which of the following is the average value of
\(f(x)\) over the interval
\([0,8]\text{?}\)
Figure 117. Plot of \(f(x)\text{.}\)
Note
\(f(x)=\begin{cases} 1, & 0\leq x\leq 3 \\ 4, & 3 < x \leq 6 \\ 2, & 6 < x \leq 8 \end{cases}\text{.}\)
\(\displaystyle 4\)
\(\displaystyle 2\)
\(\displaystyle \displaystyle \frac{7}{3}\)
\(\displaystyle 19\)
\(\displaystyle 2.375\)
Subsection 6.1.2 Videos
Figure 118. Video: Compute the average value of a function on an interval
Subsection 6.1.3 Exercises