The linear approximation (or tangent line approximation or linearization) of a function \(f(x)\) at \(x=a\) is the tangent line \(L(x)\) at \(x=a\text{.}\) In formulas, \(L(x)\) is the linear function
Notice that this is obtained by writing the tangent line to \(f(x)\) at \((a,f(a))\) in point-slope form and calling the resulting linear function \(L(x)\text{.}\) The linear approximation \(L(x)\) is a linear function that looks like \(f(x)\) when we zoom in near \(x=a\text{.}\)
Find the equation of the tangent line to \(\ln(x)\) at \(x=1\text{.}\) This will be your linear approximation \(L(x)\text{.}\) What do you get for \(L(x)\text{?}\)
Using the equation of the tangent line to the graph of \(\ln(x)\) at \(x=1\) and the shape of this graph, you can show that for all values of \(x\text{,}\) we have that \(\ln(x) \leq x-1\text{.}\)
Compute the second derivative of \(\ln(x)\text{.}\) What do you notice about the sign of the second derivative of \(\ln(x)\text{?}\) What does this tell you about the shape of the graph?
Conclude that because the graph of \(\ln(x)\) has a certain shape, the graph will bend below the tangent line and so that \(\ln(x)\) will always be smaller than the tangent line approximation \(L(x)= x -1 \text{.}\)
Someone claims that the square root of 1.1 is about 1.05. Use the linear approximation to check this estimate. Do you think this estimate is about right? Why or why not?
If a function \(f(x)\) is concave up around \(x=a\text{,}\) then the function is turning upwards from its tangent line. So when we use a linear approximation, the value of the approximation will be below the actual value of the function and the approximation is an underestimate. If a function \(f(x)\) is concave down around \(x=a\text{,}\) then the function is turning downwards from its tangent line. So when we use a linear approximation, the value of the approximation will be above the actual value of the function and the approximation is an overestimate.
Suppose \(f\) has a continuous positive second derivative and \(\Delta x\) is a small increment in \(x\) (like \(h\) in the limit definition of the derivative). Which one is larger...
\begin{equation*}
f(1 + \Delta x ) \quad \text{or} \quad f'(1) \Delta x + f(1) \quad?
\end{equation*}
Suppose that \(p'(7)=0\) and you know that \(p''(x) < 0\) for \(x < 7\text{.}\) Explain how to determine if your estimate of \(p(6.951)\) is too large or too small.
Suppose that \(p''(x) > 0\) for \(x > 7\text{.}\) Use this fact and the additional information above to sketch an accurate graph of \(y=p(x)\) near \(x=7\text{.}\)
We want to choose \(a,b,c\) such that our quadratic polynomial resembles \(f(x)\) at \(x=1\text{.}\) First thing, we want \(f(1)=q(1)\text{.}\) What equation in \(a,b,c\) does this condition give you?
Find a solution to this system of linear equations! Your answer will give you values of \(a,b,c\) that can be used to draw a quadratic approximating the natural logarithm. You can check your answer on Desmos https://www.desmos.com/calculator/bad2xrwmvl
Find the linear approximation \(L(x)\) of \(\cos(x)\) at \(x=0\text{.}\) Then find the quadratic approximation \(Q(x)\) of \(\cos(x)\) at \(x=0\text{.}\) Graph both and compare the two approximations!